Question

Тело брошено вертикально вверх со скоростью 20 м/с.На какой высоте его кинетическая энергия будет равна потенциальной?

Answer 1

Ек=Еп
Ek=mv^2/2
Eп=mgh
mgh=mv^2/2
h=v^2/2g  Скорость сокращается! 
h=400/20=20м

Answer 2

Calculation of the Height at which Kinetic Energy is Equal to Potential Energy

To determine the height at which the kinetic energy of the body is equal to its potential energy, we need to equate the two energies and solve for the height.

Let's assume the mass of the body is m and its initial velocity is v.

The kinetic energy of the body is given by the formula: KE = (1/2)mv^2.

The potential energy of the body at a height h is given by the formula: PE = mgh, where g is the acceleration due to gravity.

To find the height at which the kinetic energy is equal to the potential energy, we can set the two equations equal to each other and solve for h:

(1/2)mv^2 = mgh

Simplifying the equation, we can cancel out the mass m:

(1/2)v^2 = gh

Now, we can solve for h:

h = (1/2)v^2 / g

Given that the initial velocity v is 20 m/s, we can substitute this value into the equation. However, we need to know the value of the acceleration due to gravity g.

The acceleration due to gravity on Earth is approximately 9.8 m/s^2. However, the question does not specify the location, so we cannot assume a specific value for g.

Please provide the value of the acceleration due to gravity at the given location, and I will calculate the height at which the kinetic energy is equal to the potential energy.