Question

. При включении в цепь проводника радиусом 2 мм и длиной 80 м напряжение на его концах 4 В при силе тока 2А. Определите удельное сопротивление вещества проводника.

Answer 1

Решение в приложении

Answer 2

Calculation of Specific Resistance

To determine the specific resistance of the conductor, we can use the formula:

Specific Resistance (ρ) = (Resistance (R) x Cross-sectional Area (A)) / Length (L)

Given: - Radius of the conductor (r) = 2 mm = 0.002 m - Length of the conductor (L) = 80 m - Voltage across the conductor (V) = 4 V - Current through the conductor (I) = 2 A

To calculate the specific resistance, we need to find the resistance of the conductor first. The resistance can be calculated using Ohm's Law:

Resistance (R) = Voltage (V) / Current (I)

Let's calculate the resistance:

Resistance (R) = 4 V / 2 A = 2 Ω Now, we can calculate the cross-sectional area (A) of the conductor using the formula:

Cross-sectional Area (A) = π x (Radius (r))^2

Cross-sectional Area (A) = π x (0.002 m)^2

Cross-sectional Area (A) ≈ 0.00001257 m^2

Now, we can calculate the specific resistance (ρ) using the formula mentioned earlier:

Specific Resistance (ρ) = (Resistance (R) x Cross-sectional Area (A)) / Length (L)

Specific Resistance (ρ) = (2 Ω x 0.00001257 m^2) / 80 m

Specific Resistance (ρ) ≈ 0.000000031425 Ω·m

Therefore, the specific resistance of the conductor is approximately 0.000000031425 Ω·m.

Please note that the specific resistance value is an approximation and may vary depending on the material of the conductor.