Question

Сосуд, содержащий некоторую массу азота при н.у. ( температура нулевая = 0 градусов цельсия, давление нулевое = 10^5 Па), движется со скоростью 100 м/с. Удельная теплоемкость азота при постоянном объеме равна 745 Дж/кг*К. При внезапной остановке сосуда максимальная температура азота будет равна?

Answer 1

Ответ   будет 280К
cm(T2-T1)=mv^2\2
t=0.67=273+0.67=280K

Answer 2

Calculation of the Maximum Temperature of Nitrogen

To calculate the maximum temperature of nitrogen in the vessel after it comes to a sudden stop, we can use the principle of conservation of energy. The initial kinetic energy of the nitrogen is converted into internal energy, resulting in an increase in temperature.

The equation for the change in internal energy of a substance is given by:

ΔU = m * c_v * ΔT

Where: - ΔU is the change in internal energy - m is the mass of the nitrogen - c_v is the specific heat capacity of nitrogen at constant volume - ΔT is the change in temperature

We can rearrange the equation to solve for ΔT:

ΔT = ΔU / (m * c_v)

To find the change in internal energy (ΔU), we can use the equation:

ΔU = 0.5 * m * v^2

Where: - v is the velocity of the nitrogen

Substituting this into the previous equation, we get:

ΔT = (0.5 * m * v^2) / (m * c_v)

Simplifying further, we have:

ΔT = 0.5 * (v^2 / c_v)

Now we can substitute the given values into the equation to calculate the maximum temperature of the nitrogen.

Given: - v = 100 m/s (velocity of the nitrogen) - c_v = 745 J/(kg*K) (specific heat capacity of nitrogen at constant volume)

ΔT = 0.5 * (100^2 / 745)

Calculating this expression, we find:

ΔT ≈ 6.71 K

Therefore, the maximum temperature of the nitrogen in the vessel after it comes to a sudden stop is approximately 6.71 degrees Celsius.