Question

1) Тело массой 3 кг движется с ускорением 0.5 м/с2. Чему равна равнодействующая всех сил, приложенных к телу?1) 1,5 Н 2) 3 Н3) 60 Н4) 6 Н2) Сила в 30 Н сообщает телу ускорение в 1,5 м/с2. Чему равен модуль силы, сообщающий этому же телу ускорение 3 м/с2? 1) 60 Н2) 15 Н3) 30 Н4) 90 Н3) Два ученика растягивают динамометр в разные стороны. Каждый прилагает силу в 30 Н. Каково показание динамометра? 4) На тело действует сила тяжести в 20 Н и горизонтальная сила в 20 Н. Каково значение модуля равнодейсвующей силы?1) 20корень из 2 Н2) 40 Н3) 0 Н4) 10корень из 2 Н5)Верны ли следующие утверждения?А. Существуют такие системы отсчёта, относительно которых тела сохраняют свою скорость неизменной, если на них не действуют другие тела.Б. Силы с которыми тела действуют друг на друга, равны по модулю и противоположны по направлению.1) верно только А2)верно только Б3) верно и А, и Б4) оба утверждения неверны6) Произошло столкновение двух вагонов. В результате чего первый вагон массой 20 т получил ускорение- 5 м/с2. Какое ускорение получил второй вагон, если его масса- 25 т? 1) 4 м/с2 2) 6 м/с2 3) 2 м/с2 4) 1 м/с2

Answer 1

1.1,5Н
2.60Н
3.0
4.40
6.6М/С

Answer 2

Question 1:

A body with a mass of 3 kg is moving with an acceleration of 0.5 m/s^2. What is the resultant of all the forces applied to the body?

The resultant force acting on an object is equal to the product of its mass and acceleration, according to Newton's second law of motion (F = ma).

Given: Mass (m) = 3 kg Acceleration (a) = 0.5 m/s^2

To find the resultant force, we can use the formula:

Resultant force (F) = mass (m) * acceleration (a)

Substituting the given values, we have:

F = 3 kg * 0.5 m/s^2 F = 1.5 N

Therefore, the resultant force acting on the body is 1.5 N.

Question 2:

A force of 30 N provides an acceleration of 1.5 m/s^2 to an object. What is the magnitude of the force that would provide the same object with an acceleration of 3 m/s^2?

The relationship between force, mass, and acceleration is given by Newton's second law of motion (F = ma).

Given: Force (F1) = 30 N Acceleration (a1) = 1.5 m/s^2 Acceleration (a2) = 3 m/s^2

To find the magnitude of the force (F2) that would provide the same object with an acceleration of 3 m/s^2, we can use the formula:

F2 = (F1 * a2) / a1

Substituting the given values, we have:

F2 = (30 N * 3 m/s^2) / 1.5 m/s^2 F2 = 60 N

Therefore, the magnitude of the force that would provide the same object with an acceleration of 3 m/s^2 is 60 N.

Question 3:

Two students pull a dynamometer in opposite directions with a force of 30 N each. What is the reading on the dynamometer?

The reading on the dynamometer will be equal to the sum of the forces applied to it. In this case, each student applies a force of 30 N, so the total force acting on the dynamometer is:

Total force = 30 N + 30 N = 60 N

Therefore, the reading on the dynamometer is 60 N.

Question 4:

A body is acted upon by a gravitational force of 20 N and a horizontal force of 20 N. What is the value of the resultant force?

The resultant force can be found by summing up the individual forces acting on the body. In this case, there is a vertical force due to gravity and a horizontal force.

Given: Vertical force (F1) = 20 N Horizontal force (F2) = 20 N

To find the value of the resultant force (F), we can use the Pythagorean theorem:

F = sqrt(F1^2 + F2^2)

Substituting the given values, we have:

F = sqrt((20 N)^2 + (20 N)^2) F = sqrt(400 N^2 + 400 N^2) F = sqrt(800 N^2) F ≈ 28.28 N

Therefore, the value of the resultant force is approximately 28.28 N.

Question 5:

Are the following statements true?

A. There exist reference frames in which objects maintain their velocity unchanged if no external forces act on them. B. The forces with which bodies act on each other are equal in magnitude and opposite in direction.

Statement A is true. In inertial reference frames, objects will maintain their velocity unchanged if no external forces act on them. This is known as Newton's first law of motion or the law of inertia.

Statement B is also true. According to Newton's third law of motion, forces always occur in pairs. These forces are equal in magnitude and opposite in direction. For every action, there is an equal and opposite reaction.

Therefore, both statements A and B are true.

Question 6:

Two wagons collide, and as a result, the first wagon with a mass of 20 t experiences an acceleration of -5 m/s^2. What acceleration does the second wagon with a mass of 25 t experience?

According to Newton's second law of motion (F = ma), the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

Given: Mass of the first wagon (m1) = 20 t Acceleration of the first wagon (a1) = -5 m/s^2 Mass of the second wagon (m2) = 25 t

To find the acceleration of the second wagon (a2), we can use the formula:

a2 = (m1 * a1) / m2

Substituting the given values, we have:

a2 = (20 t * -5 m/s^2) / 25 t a2 = -100 m/s^2 / 25 a2 = -4 m/s^2

Therefore, the second wagon experiences an acceleration of -4 m/s^2.