Question

Два проводника сопротивлением 2 ом и один 3 ом подключены к элементу с эдс 1,5В. Внутреннее сопротивление источника тока 0,5 ом. Найдите силу тока в каждом сопротивлении

Answer 1

R1 = 2 Ом
R2 = 3 Ом
E= 1,5 В
r =0.5 Ом
I=?
I=E/R+r
I1=1,5/2+0,5 = 0,6 А
I2=1,5/3+0.5= 0,43 А

Answer 2

Calculation of Current in Each Resistor

To find the current in each resistor, we can use Ohm's Law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by its resistance.

Given: - Resistance of the first conductor (R1) = 2 Ω - Resistance of the second conductor (R2) = 3 Ω - Electromotive force (EMF) of the source (E) = 1.5 V - Internal resistance of the source (r) = 0.5 Ω

We can calculate the current in each resistor using the following formulas:

For the first conductor: I1 = (E - V_internal) / R1 For the second conductor: I2 = (E - V_internal) / R2 where: - I1 is the current flowing through the first conductor (in Amperes) - I2 is the current flowing through the second conductor (in Amperes) - V_internal is the voltage drop across the internal resistance of the source (in Volts)

To find the voltage drop across the internal resistance of the source (V_internal), we can use Ohm's Law again: V_internal = I_total * r where: - I_total is the total current flowing through the circuit (in Amperes) - r is the internal resistance of the source (in Ohms)

To calculate the total current (I_total), we can use Kirchhoff's Current Law, which states that the sum of currents entering a junction is equal to the sum of currents leaving the junction. In this case, the total current is equal to the sum of the currents flowing through the two resistors: I_total = I1 + I2

Let's calculate the values:

1. Calculate the voltage drop across the internal resistance: - I_total = I1 + I2 - V_internal = I_total * r

2. Calculate the current in each resistor: - I1 = (E - V_internal) / R1 - I2 = (E - V_internal) / R2

Let's substitute the given values into the formulas and calculate the currents.