Question

При укладке асфальта рабочий вручную перемешает каток массой 50 кг с силой 4,9 H.Определите величину коэффициента трения качения.

Answer 1

Сила, с которой рабочий толкает каток, равна силе трения
Fтр = 4,9Н
m = 50кг
g = 9.8Н/м
-----------------
μ - ? коэффициент трения
--------------------
Fтр = μ · mg → μ = Fтр /mg = 4.9 / (50 · 9.8) = 0.01
-------------------------
Ответ: 0,01

Answer 2

Calculation of the Coefficient of Rolling Friction

To determine the coefficient of rolling friction, we can use the equation:

F = μ * N

Where: - F is the force of rolling friction - μ is the coefficient of rolling friction - N is the normal force

In this case, the force of rolling friction is equal to the force applied by the worker to the roller, which is 4.9 H (H stands for hectonewton, which is equal to 100 newtons). The normal force is equal to the weight of the roller, which can be calculated using the formula:

N = m * g

Where: - m is the mass of the roller - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Given that the mass of the roller is 50 kg, we can calculate the normal force:

N = 50 kg * 9.8 m/s^2 = 490 N

Now we can substitute the values into the equation for rolling friction:

4.9 H = μ * 490 N

Simplifying the equation, we find:

μ = 4.9 H / 490 N = 0.01

Therefore, the coefficient of rolling friction in this case is 0.01.

Please note that the sources provided did not contain specific information about the coefficient of rolling friction for manually operated rollers. The calculation provided is based on the general principles of rolling friction.