Question

Лыжник начинает скользить с горы с ускорением 0 3 метра в секунду в квадрате Найдите его перемещение через 20 секунд после начала движения

Answer 1

Vo=0 м/с,а =0,3 м/с2;t=20c, найти s(20)-? Решение: s(t)=Vot+at^2/2; S(20)=0+0,3*20*20/2=60 м

Answer 2

Дано:
а=0,3 м/с2
t=20с
Найти:
S-?
Решение:
S=$\frac{at^2}{2}$
S=$\frac{0.3*20^2}{2}$=$\frac{0.3*400}{2}$=60 м
Ответ: 60м

Answer 3

Calculation of Displacement

To calculate the displacement of the skier after 20 seconds, we need to use the equation of motion:

s = ut + (1/2)at^2

where: - s is the displacement - u is the initial velocity - t is the time - a is the acceleration

In this case, the skier starts with an initial velocity of 0 m/s and has an acceleration of 0.3 m/s^2 Plugging in the values:

s = (0)(20) + (1/2)(0.3)(20)^2

Simplifying the equation:

s = 0 + (1/2)(0.3)(400)

s = 0 + (0.15)(400)

s = 60 meters

Therefore, the displacement of the skier after 20 seconds is 60 meters.

Conclusion

The skier will have a displacement of 60 meters after 20 seconds of starting to slide down the hill with an acceleration of 0.3 m/s^2.