Question

Счастливый жених, масса которого 70 кг несет на руках красавицу невесту, масса которой 110 кг. С какой силой эта парочка давит на пол лифта, если он движется вниз с ускорением 2 м/с? Решите пожалуйста :3

Answer 1

Эта парочка будет давить на пол лифта с силой равной силой тяжести.Так вот Fтяж=m(g-a) так как лифт движется вниз g=10м/с-это ускор. своб. падения, а-есть ускорение лифта=2м/с , m-масса тела, в нашем случае 70 кг +110кг=180 кг
всё считаем силу =180*(10-2)=180*8=1400Н

Answer 2

Problem Analysis

To solve this problem, we need to determine the force with which the couple is pressing on the floor of the elevator. We are given the masses of the bride and groom, as well as the acceleration of the elevator. We can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Solution

To find the force exerted by the couple on the floor of the elevator, we can calculate the net force acting on them. The net force is equal to the sum of the forces exerted by the bride and groom.

Let's denote the mass of the groom as m1 (70 kg) and the mass of the bride as m2 (110 kg). The acceleration of the elevator is given as a (-2 m/s^2, since it is moving downward).

The force exerted by the groom on the floor of the elevator is given by F1 = m1 * a. Similarly, the force exerted by the bride on the floor of the elevator is given by F2 = m2 * a.

The net force exerted by the couple on the floor of the elevator is the sum of these two forces: F_net = F1 + F2.

Let's calculate the force exerted by the couple on the floor of the elevator:

F1 = m1 * a = 70 kg * (-2 m/s^2) = -140 N (force exerted by the groom)

F2 = m2 * a = 110 kg * (-2 m/s^2) = -220 N (force exerted by the bride)

F_net = F1 + F2 = -140 N + (-220 N) = -360 N

Therefore, the couple exerts a force of -360 N on the floor of the elevator.

Note: The negative sign indicates that the force is directed downward, which is consistent with the downward acceleration of the elevator.

Answer

The couple exerts a force of -360 N on the floor of the elevator as it moves downward with an acceleration of 2 m/s^2.