Question

Через графитовый проводник в форме параллелепипеда длиной l=3см и площадью поперечного сечения S=30мм^2 идет ток I=5A.Найти падение напряжения на концах графитового проводника

Answer 1

Дано:  L = 0,03 м, S = 30 мм², I = 5 A.
Графит ρ = 8 Ом*мм²/м

R = ρL/S = 8*0,03/30 = 0,008 Ом. 
U = I*R = 5*0,008 = 0,04 В.

Answer 2

Calculation of Voltage Drop on Graphite Conductor

To calculate the voltage drop on the ends of a graphite conductor, we need to use Ohm's Law, which states that the voltage drop (V) across a conductor is equal to the product of the current (I) flowing through it and the resistance (R) of the conductor. Mathematically, it can be expressed as:

V = I * R

In this case, we are given the length (l) of the graphite conductor as 3 cm and the cross-sectional area (S) as 30 mm^2. However, we don't have the resistance value directly. To find the resistance, we can use the formula:

R = ρ * (l / S)

where ρ is the resistivity of the graphite material.

Unfortunately, the specific resistivity value for graphite is not provided in the given information. Therefore, we cannot calculate the exact voltage drop without this crucial information. The resistivity of graphite can vary depending on factors such as impurities and temperature. If you have the specific resistivity value for the graphite material, please provide it so that we can proceed with the calculation.