Question

Хоккеист массой 65 кг равномерно движется по льду на коньках.коэффициент трения равен 0.02.определить силу трения коньков о лёд

Answer 1

F=uN N=mg F=umg F=0.02*10*65=13H

Answer 2

Calculation of Frictional Force

To determine the frictional force between the skates and the ice, we can use the formula:

Frictional Force = Coefficient of Friction × Normal Force

In this case, the coefficient of friction is given as 0.02. However, the normal force is not provided. The normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface.

Since the skater is moving uniformly, we can assume that the normal force is equal to the weight of the skater. The weight can be calculated using the formula:

Weight = Mass × Acceleration due to Gravity

Given that the mass of the hockey player is 65 kg, we can use the standard acceleration due to gravity of 9.8 m/s^2.

Let's calculate the weight first:

Weight = 65 kg × 9.8 m/s^2

Using the above formula, we find that the weight of the hockey player is 637 N (rounded to the nearest whole number).

Now we can calculate the frictional force:

Frictional Force = 0.02 × 637 N

Using the above formula, we find that the frictional force between the skates and the ice is approximately 12.74 N (rounded to two decimal places).

Therefore, the force of friction between the skates and the ice is approximately 12.74 N.