Question

На баллоне одной первой лампы написано 120 В; 100 Вт, а на баллоне второй — 220 В; 100 Вт. Лампы включены в сеть с напряжением, на которое они рассчитаны. У какой лампы сила тока больше; во сколько раз?

Answer 1

P=IU-мощность - I=P÷U
I1=100/120≈0,83A
I2=100/220≈0,45A
I1/I2≈1,8

Answer 2

Answer:

The first lamp is rated at 120V, 100W, while the second lamp is rated at 220V, 100W. We need to determine which lamp has a greater current and by how many times.

Calculation:

To find the current for each lamp, we can use the formula: Power (W) = Voltage (V) × Current (A).

For the first lamp: - Power (W) = 100W - Voltage (V) = 120V - Current (A) = Power (W) / Voltage (V) = 100W / 120V = 0.8333A

For the second lamp: - Power (W) = 100W - Voltage (V) = 220V - Current (A) = Power (W) / Voltage (V) = 100W / 220V = 0.4545A

Conclusion:

- The first lamp has a greater current of approximately 0.8333A compared to the second lamp's current of approximately 0.4545A. - The current in the first lamp is approximately 1.83 times greater than the current in the second lamp.

This calculation shows that the first lamp has a higher current compared to the second lamp.