Question

Пожалуйста помогите. первые 9 км автобус прошел со скоростью 36 км/ч, а следующие 27 км - со скоростью 54 км/ч . Какова средняя скорость автобуса?пожалуйста решите.

Answer 1

Дано:

s1=9км

v1=36км/ч

s2=27км

v2=54км/ч

vср-?

Решение:

vср=S1+S2/t1+t2

t1=S1/v1=9/36=0,25ч

t2=27/54=0,5ч

vср=9+27/0,5+0,25=36/0,75=48км/ч

Ответ:48км/ч

Answer 2

Calculation of Average Speed

To calculate the average speed of the bus, we need to find the total distance traveled and the total time taken.

The bus traveled the first 9 km at a speed of 36 km/h and the next 27 km at a speed of 54 km/h.

To find the total distance traveled, we add the distances traveled at each speed: 9 km + 27 km = 36 km.

To find the total time taken, we divide the total distance by the average speed: 36 km / average speed = total time.

Now, let's calculate the average speed of the bus.

Solution

Let's assume the average speed of the bus is x km/h.

The time taken to travel the first 9 km at a speed of 36 km/h is given by: 9 km / 36 km/h = 0.25 hours.

The time taken to travel the next 27 km at a speed of 54 km/h is given by: 27 km / 54 km/h = 0.5 hours.

The total time taken is the sum of the times taken at each speed: 0.25 hours + 0.5 hours = 0.75 hours.

We can now calculate the average speed using the formula: average speed = total distance / total time.

Substituting the values, we have: x km/h = 36 km / 0.75 hours.

Simplifying the equation, we get: x km/h = 48 km/h.

Therefore, the average speed of the bus is 48 km/h.

Answer

The average speed of the bus is 48 km/h.