Question

Определите ток I в цепи батареи, образованной последовательным соединением трех одинаковых гальванических элементов и питающей нагрузку с сопротивлением Rн = 9 Ом. ЭДС каждого гальванического элемента Е = 1,5 В, внутреннее сопротивление R0 = 3 Ом. ПОМОГИТЕ ПОЖАЛУЙСТА , ВСЕ ПОДРОБНО НУЖНО СДЕЛАТЬ

Answer 1

I=e/(R+r)
I=1,5/(3+9)

Answer 2

Calculation of Current in the Battery Circuit

To determine the current in the battery circuit, we need to consider the series connection of three identical galvanic elements and the load with a resistance of Rн = 9 Ω. Each galvanic element has an electromotive force (EMF) of E = 1.5 V and an internal resistance of R0 = 3 Ω.

The total resistance in the circuit can be calculated by summing the internal resistances of the galvanic elements and the load resistance:

Total resistance (R) = 3R0 + Rн

Substituting the given values, we have:

R = 3(3 Ω) + 9 Ω = 18 Ω

The total resistance in the circuit is 18 Ω.

To calculate the current (I) in the circuit, we can use Ohm's Law:

I = E / R

Substituting the given values, we have:

I = (1.5 V) / (18 Ω) = 0.083 A

Therefore, the current in the battery circuit is 0.083 A.

Please note that the calculations provided above are based on the given information and assumptions. If there are any additional factors or details that need to be considered, please let me know.