Question

Помогите пжж.. Под действием силы упругости 250 Н пружина растянулась на 0,3метра.Найти потенциальную энергию пружины и работу силы упругости.Как изменится потенциальная энергия пружины,если под действием силы упругости пружина растянется еще на 0,2метра?

Answer 1

Fупр=кх к=250/0.3=833.34

Wп=кх^2/2=833,34*0.3^2/2=37.5

A=Fx=250*0.3=75

к'=250/0.5=500

Wп'=500*0.5^2/2=62.5

Answer 2

Calculation of Potential Energy and Work Done by the Spring

To calculate the potential energy and work done by the spring, we can use the formula:

Potential Energy (PE) = (1/2) * k * x^2

where: - PE is the potential energy of the spring, - k is the spring constant, - x is the displacement of the spring from its equilibrium position.

In this case, the spring is stretched by a force of 250 N and is displaced by 0.3 meters. Therefore, we can calculate the potential energy as follows:

PE = (1/2) * 250 N * (0.3 m)^2

Let's calculate the potential energy:

PE = (1/2) * 250 N * (0.3 m)^2 = 11.25 J

The potential energy of the spring is 11.25 Joules.

Now, let's calculate the work done by the spring. The work done by the spring is equal to the change in potential energy. Since the spring is stretched by an additional 0.2 meters, the change in displacement is 0.2 meters. Therefore, the work done by the spring can be calculated as:

Work = PE_final - PE_initial

where: - PE_final is the potential energy of the spring after the additional displacement, - PE_initial is the initial potential energy of the spring.

Let's calculate the work done by the spring:

Work = PE_final - PE_initial = (1/2) * 250 N * (0.5 m)^2 - (1/2) * 250 N * (0.3 m)^2

Work = (1/2) * 250 N * [(0.5 m)^2 - (0.3 m)^2]

Work = (1/2) * 250 N * [0.25 m^2 - 0.09 m^2]

Work = (1/2) * 250 N * 0.16 m^2

Work = 20 J

The work done by the spring is 20 Joules.

Change in Potential Energy of the Spring

To calculate the change in potential energy of the spring, we need to consider the change in displacement. In this case, the spring is stretched by an additional 0.2 meters. Therefore, the change in displacement is 0.2 meters.

The change in potential energy can be calculated using the formula:

Change in Potential Energy = (1/2) * k * (change in x)^2

where: - Change in Potential Energy is the difference in potential energy, - k is the spring constant, - change in x is the change in displacement.

Let's calculate the change in potential energy:

Change in Potential Energy = (1/2) * 250 N * (0.2 m)^2

Change in Potential Energy = 5 J

The change in potential energy of the spring is 5 Joules.

Therefore, if the spring is stretched by an additional 0.2 meters, the potential energy of the spring will increase by 5 Joules.

I hope this helps! Let me know if you have any further questions.