Question

Луч на поверхность вещества под углом 60° к горизонту угол преломления луча равен 30°. найдите показатель преломления вещества

Answer 1

Sina/sinb=nsin60/sin30=0,866/0,5=1,73
n=1,73

Answer 2

Calculation of the Refractive Index

To find the refractive index of the substance, we can use Snell's law, which relates the angles of incidence and refraction to the refractive index of the medium. Snell's law is given by:

n₁ sin(θ₁) = n₂ sin(θ₂)

Where: - n₁ is the refractive index of the initial medium (in this case, air) - θ₁ is the angle of incidence - n₂ is the refractive index of the final medium (the substance) - θ₂ is the angle of refraction

In this case, the angle of incidence is 60° and the angle of refraction is 30°. We need to find the refractive index of the substance.

Let's substitute the given values into Snell's law:

n₁ sin(60°) = n₂ sin(30°)

Since the refractive index of air is approximately 1, we can simplify the equation:

1 * sin(60°) = n₂ * sin(30°)

Simplifying further:

√3/2 = n₂ * 1/2

n₂ = √3

Therefore, the refractive index of the substance is √3.