Question

Найдите активное сопротивление электрической лампы накаливания, включенной в цепь переменного тока с действующим напряжением 220В, если при этом на ней выделяется средняя мощность 100 Вт

Answer 1

Найдём силу тока I = P/U = 100/220 = 0.45А
найдём активное сопротивление лампы по закону Ома R = U/I = 220/0.45 = 488.8Ом

Answer 2

Finding the Active Resistance of an Incandescent Lamp

To find the active resistance of an incandescent lamp connected to an AC circuit with an effective voltage of 220V and an average power of 100W, we can use the formula:

Active Power (P) = (Effective Voltage (V)^2) / Active Resistance (R)

Given that the average power is 100W and the effective voltage is 220V, we can rearrange the formula to solve for the active resistance:

Active Resistance (R) = (Effective Voltage (V)^2) / Active Power (P)

Substituting the values, we get:

Active Resistance (R) = (220^2) / 100

Calculating this, we find:

Active Resistance (R) = 48400 / 100 = 484 Ω

Therefore, the active resistance of the incandescent lamp is 484 Ω.