Question

тело массой 1 кг движется равномерно по окружности со скоростью 2 м/с.Определите изменение импульса тела после того,как оно пройдёт четверть окружности.

Answer 1

направление импульса совпадает  с направлением скорости

четверть окружности это 90 град - угол изменения направления скорости и импульса

Δp =↑p1-↑p2 -векторная разность

скалярная величина p1=p2=p=mv

скалярная величина Δp =√((p2)^2+(p1)^2)=√(p^2+p^2)=p√2 =mv√2=1*2√2=2√2 =2.83 =2.8 кг*м/с

ОТВЕТ  2√2 =2.83 =2.8 кг*м/с

Answer 2

Calculating Change in Momentum of a Moving Object

When a body with a mass of 1 kg moves uniformly along a circle with a speed of 2 m/s, the change in momentum of the body after it has traveled a quarter of the circle can be calculated using the formula:

Change in momentum (\( \Delta p \)) = \( mv_2 - mv_1 \)

Where: - \( m \) = mass of the body - \( v_1 \) = initial velocity - \( v_2 \) = final velocity

Given: - \( m = 0.5 \) kg - \( v_1 = 4 \) m/s (initial velocity) - \( v_2 = 2 \) m/s (final velocity)

Using the formula, we can calculate the change in momentum:

\( \Delta p = mv_2 - mv_1 \) \( \Delta p = 0.5 \times 2 - 0.5 \times 4 \) \( \Delta p = 1 - 2 \) \( \Delta p = -1 \) kg m/s

The negative sign indicates that the direction of the momentum has changed.

Therefore, the change in momentum of the body after it has traveled a quarter of the circle is -1 kg m/s.

This calculation is based on the provided information and the formula for change in momentum.