Question

Какой путь проходит свободно падающая капля за 4 секунды?

Answer 1

V=gt
v - время
g - константа, равная 9,8м/с(10 - приближенно)
t - время
4×9,8 = 39,2м(40м приближенно)
Не забывай про лучший ответ.

Answer 2

Path of a Freely Falling Drop in 4 Seconds

A freely falling drop covers a specific distance in a given time. The distance covered by a freely falling drop in 4 seconds can be calculated using the formula:

Distance (d) = 1/2 * g * t^2

Where: - g is the acceleration due to gravity (approximately 9.81 m/s^2 on the surface of the Earth) - t is the time in seconds

Using this formula, the distance covered by a freely falling drop in 4 seconds can be calculated as follows:

d = 1/2 * g * t^2 d = 1/2 * 9.81 * 4^2 d = 1/2 * 9.81 * 16 d = 78.48 meters

Therefore, a freely falling drop covers approximately 78.48 meters in 4 seconds.

This calculation is based on the standard formula for the distance covered by an object in free fall under the influence of gravity