Question

Охотник выстрелил из винтовки ствол которой располагался горизонтально .пуля упала на расстоянии 424 м от охотника .определите рост охотника пренебрегая сопротивлением воздуха и полагая g=10 м/с. начальная скорость пули равна 707 м/с.

Answer 1

T=S/V=424/707=0,6 c
h=g*t^2/2=10*0,6^2/2=1,8 м

Answer 2

Calculating the Hunter's Height

To calculate the hunter's height, we can use the following kinematic equation:

h = v^2 * sin^2(θ) / (2 * g)

Where: - h = vertical distance traveled by the bullet (424 m) - v = initial velocity of the bullet (707 m/s) - θ = angle of elevation (in this case, 0 degrees as the rifle was horizontal) - g = acceleration due to gravity (10 m/s^2)

Substituting the given values, we get:

424 = (707^2 * sin^2(0)) / (2 * 10)

Solving for sin^2(0):

sin^2(0) = (424 * 2 * 10) / 707^2

sin^2(0) ≈ 0.119

Taking the square root of sin^2(0):

sin(0) ≈ 0.345

Now, we can use the trigonometric identity sin(θ) = opposite/hypotenuse to find the height of the hunter. The opposite side is the height of the hunter, and the hypotenuse is the distance the bullet traveled.

Height = Distance * sin(0)

Height ≈ 424 * 0.345

Height ≈ 146.28 meters

Conclusion

The height of the hunter, neglecting air resistance and assuming a gravitational acceleration of 10 m/s^2, is approximately 146.28 meters.