Question

Воду нагрели на 10 градусов, затратив 4,20*10 в 3 степени. Определить количество воды. С дано пожалуйста

Answer 1

Дано: Q=4.20*10^3
∆t=10°C
c= 4200

Решение: Q=cm∆t
m=Q/c∆t
m=4.20*10^3/ 10*4200
m=0.1кг

Answer 2

Given Information

The water was heated by 10 degrees, with an energy expenditure of 4.20*10^3.

Calculation

To determine the amount of water heated, we can use the formula:

Q = mcΔT

Where: - Q is the heat energy absorbed by the water - m is the mass of the water - c is the specific heat capacity of water (approximately 4.18 J/g°C) - ΔT is the change in temperature

We can rearrange the formula to solve for the mass of water:

m = Q / (c * ΔT)

Given: - ΔT = 10°C - Q = 4.20*10^3 J - c = 4.18 J/g°C

Substitute the given values into the formula to find the mass of water.

m = 4.20*10^3 J / (4.18 J/g°C * 10°C)

m = 1000 g

Answer

The amount of water heated is 1000 grams.