Question

Жесткость пружины 200 н/м С какой силой будет действовать пружина если она удлинилась на 8 см? ПОМОГИТЕ ПОЖАЛУЙСТА БУДУ ОЧЕНЬ РАДА

Answer 1

Дано: k=200 Н/м  x=0,08 м   F-?
Модуль силы F=k*x=200*0,08=16 H

Answer 2

Calculation of the Force Exerted by a Spring

To calculate the force exerted by a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force exerted by the spring, - k is the spring constant (also known as stiffness or spring rate), - x is the displacement of the spring from its equilibrium position.

In this case, the spring constant is given as 200 N/m, and the displacement of the spring is 8 cm (or 0.08 m).

Substituting these values into the equation, we can calculate the force exerted by the spring:

F = 200 N/m * 0.08 m

Calculating this expression gives us:

F = 16 N

Therefore, the force exerted by the spring when it is extended by 8 cm is 16 N.

Please note that the above calculation is based on the given spring constant and displacement.