Question

Стальной шарик свободно падает с некоторой высоты. Во сколько раз его средняя скорость на протяжении первой половины времени полета меньше, чем средняя скорость на протяжении второй половины времени полета? Сопротивлением воздуха пренебречь.

Answer 1

V=g*t
Vo=0
V1=V/2
V2=V

Vср1=(О+V/2)/2=V/4

Vср2=(V/2  +V)/2=3*V/4

Vcр2/Vср1=3 - ответ

Answer 2

Understanding the Problem

The question asks about the relationship between the average velocity of a steel ball during the first half of its fall and the second half, assuming no air resistance.

Solution

The average velocity of an object in free fall is directly related to the time it spends falling. The relationship between the average velocity during the first half of the fall and the second half can be determined using the principles of kinematics.

According to the laws of physics, the average velocity of an object in free fall is directly proportional to the time it spends falling. Therefore, the average velocity during the first half of the fall will be half of the average velocity during the second half of the fall.

This relationship can be explained using the equation for average velocity: Average Velocity = (Final Velocity + Initial Velocity) / 2.

During the first half of the fall, the initial velocity is zero, and the final velocity is the velocity at the midpoint of the fall. During the second half of the fall, the initial velocity is the velocity at the midpoint, and the final velocity is twice the velocity at the midpoint.

Therefore, the average velocity during the first half of the fall is half of the average velocity during the second half of the fall.

This relationship is consistent with the principles of kinematics and the laws of physics.

Conclusion

The average velocity of the steel ball during the first half of its fall is half of the average velocity during the second half of its fall.