Question

Самолёт пролетел по прямой 600 км.,затем повернул под прямым углом и пролетел ещё 800 км.Чему равен модуль вектора перемещения (в км) самолёта?

Answer 1

√(600^2+800^2)=√1000000=1000 км

Answer 2

Calculating the Displacement Vector

To calculate the displacement vector of the airplane, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

The displacement vector D of the airplane can be calculated using the formula: D = √(600^2 + 800^2)

Calculation

Using the given distances: D = √(600^2 + 800^2) = √(360000 + 640000) = √1000000 = 1000 km

Therefore, the modulus of the displacement vector of the airplane is 1000 km.