Question

Автомобиль массой 1,5т разогнался по горизонтальной поверхност дороги длиной 200м до скорости 72 км\час. Вычеслить силу(в Н) которая разогнала автомобиль

Answer 1

M=1500 кг
S= 200 м
V(0)=0
V(t)= 72 км/час=20 м/с
V(t)^2-V(0)^2=2*a*S---->a=V(t)^2/(2*S)=20^2/(2*200)=1 м/с
F=m*а =1500*1 H= 1.5 kH

Answer 2

M=1500 кг
s= 200 м
v0=0
v= 72 км\час=20 м/с
Работа силы равна А=F*s
По теореме о кинетической энергии А=ΔЕ (кин)=mv∧2/2-0
F*s=mv∧2/2
F=(mv∧2/2)/s=1500*400/200=3000 H=3кН

Answer 3

Calculation of the Force that Accelerated the Car

To calculate the force that accelerated the car, we can use the equation:

Force (N) = (mass (kg) * acceleration (m/s^2))

Given: - Mass of the car = 1.5 tons = 1500 kg - Distance covered = 200 m - Final velocity = 72 km/h = 20 m/s

First, we need to calculate the acceleration of the car using the formula:

Acceleration (m/s^2) = (Final velocity - Initial velocity) / Time

Since the car starts from rest, the initial velocity is 0 m/s. We can assume that the car reaches its final velocity in a constant time interval.

Using the given information, we can calculate the acceleration:

Acceleration (m/s^2) = (20 m/s - 0 m/s) / Time

Unfortunately, the time is not provided in the question. Therefore, we cannot calculate the exact acceleration and subsequently the force. If you can provide the time taken to reach the final velocity, I can help you calculate the force.