Question

Снаряд массой 20 г,движущийся со скоростью 600 м/с пробил деревянную преграду и вылетел из нее со скоростью 200 м/с.чему равна работа,совершенная силой сопротивления?чему ровна сила сопротивления,если толщина преграды 10 см?

Answer 1

M(V1)²/2 = A + m(V2)²/2 => A = m(V1)²/2 - m(V2)²/2 = 0,02 * 600²/2 - 0,02 * 200²/2 = 3200 Дж.
A = FS => F = A/S = 3200 Дж / 0,01 м = 320000 Н.

Answer 2

Calculation of Work Done by Resistance Force

To calculate the work done by the resistance force, we can use the equation:

Work = Force × Distance

In this case, the force is the resistance force, and the distance is the thickness of the barrier.

Given: - Mass of the projectile (m) = 20 g = 0.02 kg - Initial velocity of the projectile (u) = 600 m/s - Final velocity of the projectile (v) = 200 m/s - Thickness of the barrier (d) = 10 cm = 0.1 m

To find the resistance force, we can use the equation of motion:

v^2 = u^2 + 2ad

where: - v is the final velocity - u is the initial velocity - a is the acceleration - d is the distance

Rearranging the equation, we can solve for the acceleration:

a = (v^2 - u^2) / (2d)

Substituting the given values:

a = (200^2 - 600^2) / (2 * 0.1)

Now, we can calculate the resistance force using Newton's second law:

Force = mass × acceleration

Substituting the values:

Force = 0.02 × [(200^2 - 600^2) / (2 × 0.1)]

Finally, we can calculate the work done by the resistance force using the equation:

Work = Force × Distance

Substituting the values:

Work = (0.02 × [(200^2 - 600^2) / (2 × 0.1)]) × 0.1

Let's calculate the values using a calculator.