Question

Какое количество теплоты(Дж) выделится в результате N=2,6*10^13 термоядерных реакций 21Н+21Н=42Не? СМасса атома дейтерия m21H=2,01410 а.е.м,масса атома гелия m=4,00260 а.е.м

Answer 1

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Answer 2

Calculation of Released Heat Energy in Nuclear Reactions

To calculate the amount of heat energy released in a nuclear reaction, we need to use the equation E = mc^2, where E is the energy released, m is the mass difference, and c is the speed of light.

In the given reaction, 2,6*10^13 nuclear reactions of 21H + 21H → 42He occur. We are given the mass of deuterium (21H) as m21H = 2.01410 atomic mass units (a.m.u) and the mass of helium (42He) as m = 4.00260 a.m.u.

To find the mass difference, we subtract the initial mass from the final mass:

Mass difference = (2 * m21H) - m

Now, we can calculate the energy released using the equation E = mc^2:

Energy released = (Mass difference) * (speed of light)^2

Let's calculate the released heat energy:

Calculation:

Mass difference = (2 * m21H) - m Mass difference = (2 * 2.01410 a.m.u) - 4.00260 a.m.u Mass difference = 4.02820 a.m.u - 4.00260 a.m.u Mass difference = 0.02560 a.m.u

Energy released = (Mass difference) * (speed of light)^2 Energy released = 0.02560 a.m.u * (2.998 x 10^8 m/s)^2 Energy released = 0.02560 a.m.u * (8.988 x 10^16 m^2/s^2) Energy released = 2.301 x 10^15 a.m.u * m^2/s^2

To convert the energy from atomic mass units (a.m.u) to joules (J), we can use the conversion factor 1 a.m.u = 1.66053906660 x 10^-27 kg:

Energy released = (2.301 x 10^15 a.m.u * m^2/s^2) * (1.66053906660 x 10^-27 kg/a.m.u) Energy released = 3.822 x 10^-12 kg * m^2/s^2

Therefore, the amount of heat energy released in the given nuclear reaction is approximately 3.822 x 10^-12 kg * m^2/s^2 or 3.822 x 10^-12 joules (J).

Please note that the above calculation assumes complete conversion of mass into energy, which may not be the case in real-world scenarios.