Question

Напряжение на спирали лампочки равно 3,5 В, сопротивление спирали 14 Ом. Какую работу совершает ток в лампочке за 5 минут. Задача на применение формулы работы или мощности тока.

Answer 1

A=P*tP=U*U/RP=0,875BтA=0,875Вт*300сек=262,Дж

Answer 2

A=P*t
P=U*U/R
P=0,875Bт
A=0,875Вт*300сек=262,Дж

Answer 3

Calculating the Work Done by the Current in the Light Bulb

To calculate the work done by the current in the light bulb, we can use the formula for electrical work: work = voltage x charge. The charge can be expressed as charge = current x time. Therefore, the work done by the current in the light bulb can be calculated using the formula: work = voltage x current x time.

Given: - Voltage (V) = 3.5 V - Resistance (R) = 14 Ω - Time (t) = 5 minutes

Calculating the Current

First, let's calculate the current (I) using Ohm's law, which states that voltage = current x resistance. Therefore, current = voltage / resistance.

Using the given values: - Voltage (V) = 3.5 V - Resistance (R) = 14 Ω

We can calculate the current (I) as follows: ``` current = voltage / resistance current = 3.5 V / 14 Ω current ≈ 0.25 A ``` So, the current flowing through the light bulb is approximately 0.25 A.

Calculating the Work Done

Now, we can calculate the work done by the current in the light bulb using the formula work = voltage x current x time.

Given: - Voltage (V) = 3.5 V - Current (I) ≈ 0.25 A - Time (t) = 5 minutes

Converting the time to seconds: - Time (t) = 5 minutes = 5 x 60 seconds = 300 seconds

Using the formula: ``` work = voltage x current x time work = 3.5 V x 0.25 A x 300 s work = 26.25 J ``` Therefore, the work done by the current in the light bulb over 5 minutes is approximately 26.25 joules.

This calculation is based on the provided values and the formulas for electrical work and current.