Question

газ содержится в закрытом баллоне при температуре 294К и давлении 810кПа. При какой температуре давление газа будет равным 1,12 МПа

Answer 1

Газ содержится в закрытом баллоне при температуреT1= 294К и давленииP1= 810кПа. При какой температуре давление газа будет равнымP2= 1,12 МПа
T2 -  ?
P1/T1=P2/T2
T2= T1*P2/P1=294*1,12*10^6/0,81*10^6=406,5 К

Answer 2

Calculation of the new temperature:

To determine the temperature at which the gas pressure will be equal to 1.12 MPa, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of gas - R is the ideal gas constant - T is the temperature of the gas

We can rearrange the equation to solve for the new temperature:

T = PV / (nR)

Given: - Initial temperature (T1) = 294 K - Initial pressure (P1) = 810 kPa - Final pressure (P2) = 1.12 MPa = 1.12 * 1000 kPa

Let's substitute the values into the equation and calculate the new temperature:

T2 = (P2 * V) / (n * R)

Since the volume and the number of moles of gas are not provided, we can assume they remain constant. Therefore, we can cancel them out in the equation:

T2 = (P2 * V) / (n * R) = (P2 * V) / (n * R) = (P2 * V) / (n * R)

Now, let's substitute the values into the equation:

T2 = (1.12 * 1000 kPa * V) / (n * R)

Since we don't have the volume or the number of moles of gas, we cannot calculate the exact temperature. However, we can calculate the temperature difference between T1 and T2:

ΔT = T2 - T1 = [(1.12 * 1000 kPa * V) / (n * R)] - 294 K

Unfortunately, without the specific values for volume and number of moles, we cannot determine the exact temperature at which the gas pressure will be equal to 1.12 MPa.