Question

Решите задачу !Гравитационный маятник совершает 30 колебаний за 15 секунд .Определите период и частоту этих колебаний.

Answer 1

Количество дели на время тобишь 30/15=2 колебания в секунду

Answer 2

Task Solution:

To determine the period and frequency of the gravitational pendulum, we can use the formula:

Period (T) = 1 / Frequency (f)

Given that the pendulum completes 30 oscillations in 15 seconds, we can calculate the period and frequency using the provided formula.

Calculations:

Using the given data: - Number of oscillations (n) = 30 - Time taken (t) = 15 seconds

We can calculate the period (T) and frequency (f) as follows:

Period (T) = Time taken (t) / Number of oscillations (n) Frequency (f) = Number of oscillations (n) / Time taken (t)

Substituting the given values: Period (T) = 15 seconds / 30 oscillations = 0.5 seconds Frequency (f) = 30 oscillations / 15 seconds = 2 Hz

Conclusion:

Therefore, the period of the pendulum's oscillations is 0.5 seconds and the frequency is 2 Hz.