Question

Какой объем занимает кислород массой 3,2 кг при давлении 10 в пятой степени Па и температурой 275 К?

Answer 1

Мкт) V=3.2-.8.31*275/1800=4.05м в кубе

Answer 2

Calculating the Volume of Oxygen

To calculate the volume of oxygen, we can use the ideal gas law equation:

V = (nRT)/P

Where: - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin - P = pressure

First, we need to calculate the number of moles of oxygen using the given mass and molar mass of oxygen.

The molar mass of oxygen (O2) is approximately 32 g/mol.

Given mass of oxygen = 3.2 kg = 3200 g

Number of moles (n) = given mass / molar mass n = 3200 g / 32 g/mol = 100 moles

Now, we can use the ideal gas law equation to calculate the volume of oxygen.

Ideal Gas Law Calculation

V = (nRT)/P

Where: - n = 100 moles - R = ideal gas constant (8.314 J/(mol*K)) - T = temperature in Kelvin (275 K) - P = pressure (10^5 Pa)

Plugging in the values: V = (100 * 8.314 * 275) / (10^5) V ≈ 228.635 m^3

So, the volume of oxygen with a mass of 3.2 kg at a pressure of 10^5 Pa and a temperature of 275 K is approximately 228.635 m^3.