Question

Какое количество теплоты необходимо отобрать у воды массой 5 кг, имеющей температуру 10 градусов по цельсию , чтобы превратить ее в лед, имеющей температуру -30 градусов цельсия?

Answer 1

Решение на фото, успехов :)

Answer 2

Calculating Heat Transfer for Freezing Water

To calculate the amount of heat required to convert water at 10°C to ice at -30°C, we can use the formula:

Q = m * L

Where: - Q is the heat energy required (in joules) - m is the mass of the substance (in kilograms) - L is the specific latent heat of fusion for the substance (in joules per kilogram)

Specific Latent Heat of Fusion for Water

The specific latent heat of fusion for water is 334,000 joules per kilogram (J/kg).

Calculation

Given: - Mass of water, m = 5 kg - Initial temperature, T1 = 10°C - Final temperature, T2 = -30°C

We need to calculate the heat energy required to convert the water to ice.

The formula for heat transfer during a phase change is:

Q = m * L

Substituting the values: Q = 5 kg * 334,000 J/kg = 1,670,000 joules

Therefore, the amount of heat that needs to be removed from 5 kg of water at 10°C to convert it to ice at -30°C is 1,670,000 joules.