Question

Сколькл граммов водорода выделится при взаимодействии 8 моль соляной кислоты с цинком

Answer 1

Zn + 2HCl = ZnCl2 + H2
n(HCl) = 8 моль
n(H2) = 8/2 = 4 моль
V(H2) = 4*22,4 = 89,6 л

Answer 2

Hydrogen Gas Produced from the Reaction

When 8 moles of hydrochloric acid react with zinc, hydrogen gas is produced. To calculate the amount of hydrogen gas produced, we can use the balanced chemical equation for the reaction between hydrochloric acid and zinc:

Zn + 2HCl → ZnCl2 + H2

From the balanced equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Therefore, when 8 moles of hydrochloric acid react with zinc, the amount of hydrogen gas produced can be calculated as follows:

8 moles HCl × (1 mole H2 / 2 moles HCl) = 4 moles H2

So, 4 moles of hydrogen gas will be produced when 8 moles of hydrochloric acid react with zinc.

(#1)