Question

Длина меньшего плеча рычага равна 15 см большего 60см на меньшее плечо действует сила 64 н.Какую силу надо приложитьт к большому плечу что бы уравновесить рычаг .Сделай рисунок

Answer 1

F1*L1=F2*L2
64*15=х*60   х=64*15/60=16 Н

Answer 2

Problem Analysis

To solve this problem, we need to calculate the force required to balance the lever. The lever has a smaller arm of 15 cm and a larger arm of 60 cm. A force of 64 N is acting on the smaller arm. We need to find the force required to be applied to the larger arm to balance the lever.

Solution

The force required to balance the lever can be calculated using the principle of moments. The principle of moments states that for an object in equilibrium, the sum of the clockwise moments about any point is equal to the sum of the anticlockwise moments about the same point.

Let's denote: - F1 as the force acting on the smaller arm (15 cm). - F2 as the force we need to find, acting on the larger arm (60 cm).

The equation for the principle of moments is: F1 × 15 = F2 × 60

We can rearrange the equation to solve for F2: F2 = (F1 × 15) / 60

Now, let's calculate the value of F2 using the given force F1 = 64 N.

Calculation

F2 = (64 N × 15 cm) / 60 cm

F2 = 16 N

So, the force required to be applied to the larger arm to balance the lever is 16 N.

Diagram

``` |<--- 15 cm --->|<---------------- 60 cm ---------------->| | | | | | | | F1 | F2 | | | | | | | |---------------|-----------------------------------------| ```

I hope this helps! If you have further questions, feel free to ask.