Question

Моторы электровоза при движении со скоростью 72 км/ч потребляют мощность 4000 кВт.Определите силу тяги моторов при КПД равном 60%

Answer 1

N = F*V, отсюда

F = N/V = 0.6 * 4000 кВт / 72 км/ч = 2.4 10^6 Вт / 20 м/сек = 1.2 10^5 Н = 120 кН

Answer 2

Calculation of Tractive Force

To determine the tractive force of the motors on an electric locomotive moving at a speed of 72 km/h with a power consumption of 4000 kW and an efficiency of 60%, we can use the following formula:

Tractive Force = Power / (Speed * Efficiency)

Substituting the given values into the formula:

Tractive Force = 4000 kW / (72 km/h * 0.60)

To perform the calculation, we need to convert the speed from kilometers per hour to meters per second, as the SI unit for power is watts and the SI unit for speed is meters per second.

Converting the speed:

Speed = 72 km/h * (1000 m/km) / (3600 s/h) = 20 m/s

Substituting the converted values into the formula:

Tractive Force = 4000 kW / (20 m/s * 0.60)

Simplifying the equation:

Tractive Force = 4000 kW / 12 m/s = 333.33 kN

Therefore, the tractive force of the motors on the electric locomotive at a speed of 72 km/h and with a power consumption of 4000 kW and an efficiency of 60% is approximately 333.33 kN.