Question

Помогите плиз На тело объемом 10дм3 при полном погружении в жидкость действует выталкивающая сила 80Н.Какая это жидкость?

Answer 1

$F = \rho g V\\ \rho = F/(gV) = 80/(10*.01) = 800\text { kg/m}^3$

Это керосин

Answer 2

Determining the Liquid Based on Buoyant Force

To determine the type of liquid based on the given information, we can use the concept of buoyant force. The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. We can use the formula:

Buoyant force = Weight of the liquid displaced

Given: - Volume of the body (V) = 10 dm^3 - Buoyant force (F) = 80 N

We can calculate the density of the liquid using the formula:

Density = Buoyant force / Volume of the body

Calculating the Density of the Liquid

Using the given values, we can calculate the density of the liquid:

Density = Buoyant force / Volume of the body

Density = 80 N / 10 dm^3

Converting the volume to cubic meters: 1 dm^3 = 0.001 m^3 Volume = 10 dm^3 = 10 * 0.001 m^3 = 0.01 m^3

Density = 80 N / 0.01 m^3 = 8000 kg/m^3

Conclusion

Based on the given information, the density of the liquid is 8000 kg/m^3. This density corresponds to mercury, which has a density of approximately 13,600 kg/m^3. Therefore, the liquid in question is likely mercury.