Question

В первой вазе было в 4 раза меньше роз чем во второй.После того как в первую вазу добавили 16 роз, а из второй забрали 11 то их стало поровну. Сколько роз в обеих вазах

Answer 1

Х - роз было в 1-й вазе, тогда 4х - во 2-й. 
уравнение.
х+16 = 4х-11.
3х = 27.
х=9 (роз ) -было в 1-й вазе. 
4х= 36 (роз) - было во 2-й вазе.
9+36=45 (роз) было в обеих вазах. 

Answer 2

Calculating the Number of Roses in Both Vases

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of roses in each vase.

Let's denote: - x as the initial number of roses in the first vase - y as the initial number of roses in the second vase

Given: - In the first vase, there were 4 times fewer roses than in the second vase, so we have the equation: x = (1/4)y - After adding 16 roses to the first vase and removing 11 roses from the second vase, the number of roses became equal, so we have the equation: (x + 16) = (y - 11)

Solving the System of Equations

We can solve the system of equations to find the values of x and y.

First, we can substitute the value of x from the first equation into the second equation: (1/4)y + 16 = y - 11

Solving for y: (1/4)y - y = -11 - 16 (-3/4)y = -27 y = (-27) / (-3/4) y = 36

Now that we have the value of y, we can find the value of x using the first equation: x = (1/4)y x = (1/4) * 36 x = 9

Answer

So, the initial number of roses in the first vase was 9, and the initial number of roses in the second vase was 36.

Therefore, the total number of roses in both vases was 9 + 36 = 45.