Question

S(t)=3t+0.5t в квадрате помогите пожалуйста нужно найти ускорение)

Answer 1

S=3t+0,5t^2

ОСНОВНАЯ ФОРМУЛА S=V0t+at^2/2

ОТСЮДА а=0.5

V0=3

 

Answer 2

 

Из формулы S(t)=V0t+at²\2

a=1м\с²

 

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Answer 3

Calculating Acceleration

To find the acceleration (a) from the given position function S(t) = 3t + 0.5t^2, we need to take the second derivative of the position function with respect to time (t).

The position function S(t) can be expressed as: S(t) = 3t + 0.5t^2

Finding Velocity

First, let's find the velocity function by taking the first derivative of the position function with respect to time: v(t) = S'(t) = 3 + t

Finding Acceleration

Next, we'll find the acceleration function by taking the derivative of the velocity function with respect to time: a(t) = v'(t) = 1

So, the acceleration (a) is a constant value of 1.

Therefore, the acceleration of the object described by the position function S(t) = 3t + 0.5t^2 is 1.