
Тело, двигаясь из состояния покоя с ускорением 5 м/с2, достигло скорости 30 м/с, а затем, двигаясь
равномедленно, остановилось через 10 с. определить путь, пройденный телом за все время движения

Ответы на вопрос

===
s1=v²/(2*a)=900/(2*5)=90 м
s2=(v+0)*t/2=30*10/2=150 м
s=s1+s2=90+150=240 м
==========================



Calculation of the Distance Traveled by the Body
To calculate the distance traveled by the body, we need to consider the different stages of its motion.
1. Stage 1: Acceleration from rest to a velocity of 30 m/s
The body starts from rest and accelerates with an acceleration of 5 m/s^2 until it reaches a velocity of 30 m/s. We can use the equation of motion to calculate the time taken to reach this velocity:
``` v = u + at 30 = 0 + 5t t = 6 seconds ```
Now, we can calculate the distance covered during this stage using the equation of motion:
``` s = ut + (1/2)at^2 s = 0 + (1/2)(5)(6)^2 s = 90 meters ```
2. Stage 2: Constant velocity motion
After reaching a velocity of 30 m/s, the body continues to move at a constant velocity for 10 seconds. Since the velocity is constant, the distance covered during this stage can be calculated using the formula:
``` s = vt s = 30 * 10 s = 300 meters ```
3. Stage 3: Deceleration to rest
Finally, the body decelerates and comes to rest over a period of 10 seconds. Since the body is decelerating, the acceleration is negative (-5 m/s^2). We can calculate the distance covered during this stage using the equation of motion:
``` v = u + at 0 = 30 + (-5)t t = 6 seconds ```
Now, we can calculate the distance covered during this stage using the equation of motion:
``` s = ut + (1/2)at^2 s = 30 * 6 + (1/2)(-5)(6)^2 s = 180 - 90 s = 90 meters ```
Total Distance Traveled
To find the total distance traveled by the body, we add up the distances covered in each stage:
``` Total distance = Distance in Stage 1 + Distance in Stage 2 + Distance in Stage 3 Total distance = 90 + 300 + 90 Total distance = 480 meters ```
Therefore, the body traveled a total distance of 480 meters during its entire motion.


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