Question

ЭДС источника 10В,внутреннее сопротивление 2 Ом;сопротивление нагрузки R=18 Ом.Найти силу тока,напряжение на нагрузке,мощность тока на назагрузке,тепло,которое выделится на загрузке за 10 с?

Answer 1

Сначала I= ЭДС\R+r=> 10В\20 Ом= 0,5 А
I=U\R=> U=I*R=> 0,5А*18 Ом=9В
P(мощность)=I^2*R=0,5^2*18=4,5 Вт
Q=I^2*R*t=0,25*18*10=45дж

Answer 2

Calculation of Current, Voltage, Power, and Heat Dissipation

To find the current, voltage, power, and heat dissipation in the given circuit, we can use Ohm's Law and the power formulas.

Given: - EMF (electromotive force) of the source (E) = 10V - Internal resistance of the source (r) = 2Ω - Load resistance (R) = 18Ω - Time (t) = 10s

Calculating Current (I)

The total resistance in the circuit is the sum of the internal resistance and the load resistance: Total resistance (R_total) = r + R

Using Ohm's Law, we can calculate the current (I) flowing through the circuit: I = E / R_total

Substituting the given values: I = 10V / (2Ω + 18Ω)

Simplifying the expression: I = 10V / 20Ω I = 0.5A

Therefore, the current flowing through the circuit is 0.5A.

Calculating Voltage across the Load (V_load)

The voltage across the load can be calculated using Ohm's Law: V_load = I * R

Substituting the given values: V_load = 0.5A * 18Ω

Simplifying the expression: V_load = 9V

Therefore, the voltage across the load is 9V.

Calculating Power on the Load (P_load)

The power on the load can be calculated using the formula: P_load = I^2 * R

Substituting the given values: P_load = (0.5A)^2 * 18Ω

Simplifying the expression: P_load = 0.25A^2 * 18Ω P_load = 4.5W

Therefore, the power on the load is 4.5W.

Calculating Heat Dissipation on the Load (Q_load)

The heat dissipation on the load can be calculated using the formula: Q_load = P_load * t

Substituting the given values: Q_load = 4.5W * 10s

Simplifying the expression: Q_load = 45J

Therefore, the heat dissipated on the load over 10 seconds is 45J.

Please let me know if you need any further assistance!