
Тело движется по окружности радиусом 20 см. Период обращения = 9,28с. Найти линейную и угловую
скорости, ускорения тела.

Ответы на вопрос




Given Information:
- Radius of the circle: 20 cm - Period of revolution: 9.28 sLinear Velocity:
The linear velocity of an object moving in a circle is given by the formula:v = 2πr / T
where: - v is the linear velocity - r is the radius of the circle - T is the period of revolution
Substituting the given values:
v = 2π(20 cm) / 9.28 s
To calculate the linear velocity, we need to convert the radius from centimeters to meters:
v = 2π(0.2 m) / 9.28 s
Simplifying the equation:
v ≈ 0.135 m/s Therefore, the linear velocity of the object is approximately 0.135 m/s.
Angular Velocity:
The angular velocity of an object moving in a circle is given by the formula:ω = 2π / T
where: - ω is the angular velocity - T is the period of revolution
Substituting the given value:
ω = 2π / 9.28 s
Simplifying the equation:
ω ≈ 0.677 rad/s Therefore, the angular velocity of the object is approximately 0.677 rad/s.
Linear Acceleration:
The linear acceleration of an object moving in a circle is given by the formula:a = v^2 / r
where: - a is the linear acceleration - v is the linear velocity - r is the radius of the circle
Substituting the given values:
a = (0.135 m/s)^2 / 0.2 m
Simplifying the equation:
a ≈ 0.091 m/s^2 Therefore, the linear acceleration of the object is approximately 0.091 m/s^2.
Angular Acceleration:
The angular acceleration of an object moving in a circle is given by the formula:α = ω^2 / r
where: - α is the angular acceleration - ω is the angular velocity - r is the radius of the circle
Substituting the given values:
α = (0.677 rad/s)^2 / 0.2 m
Simplifying the equation:
α ≈ 2.29 rad/s^2 Therefore, the angular acceleration of the object is approximately 2.29 rad/s^2.
To summarize: - Linear velocity: 0.135 m/s - Angular velocity: 0.677 rad/s - Linear acceleration: 0.091 m/s^2 - Angular acceleration: 2.29 rad/s^2


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