Question

Тело соскальзывающего по наклонной плоскости проходит за 10 секунд путь 2 м начальная скорость равна нулю Определите модуль ускорения тела

Answer 1

T=10
S=2
S=at^2/2
a=S/(t^2/2)=2/(10^2/2)=2/50=4/100
a=0,04

Answer 2

Problem Analysis

We are given the following information: - The body slides down a inclined plane. - The body takes 10 seconds to cover a distance of 2 meters. - The initial velocity of the body is zero.

We need to determine the magnitude of the body's acceleration.

Solution

To solve this problem, we can use the equations of motion for uniformly accelerated motion. The equation that relates distance, time, initial velocity, and acceleration is:

distance = initial velocity * time + (1/2) * acceleration * time^2 In this case, the initial velocity is zero, so the equation simplifies to:

distance = (1/2) * acceleration * time^2 We can rearrange this equation to solve for acceleration:

acceleration = (2 * distance) / (time^2) Substituting the given values, we have:

acceleration = (2 * 2) / (10^2) = 0.04 m/s^2

Therefore, the magnitude of the body's acceleration is 0.04 m/s^2.

Answer

The magnitude of the body's acceleration is 0.04 m/s^2.