Question

Двигатель мотороллера развивает мощность 3, 3 кВт при скорости 58 км/ч.Сколько километров пройдет мотороллер,израсходовав 3, 2 л бензина,если КПД двигателя 20%? Ответьте пж срочно!!!

Answer 1

Переводим число 58 в систему СИ 58=58000

v=58000/3600=145/9 м.с

n=0.2  P=0.75 кг/л  V=3.2 л  q=46000000 Дж/кг   N=3300 Вт 

отсюда следует то что: s=vt=vnQ/N=vnPVq/N =>

=> 145/9*0,2*0,75*3,2*46000000/3300=107798метров

ответ: 107798 метров

Answer 2

Calculating the Distance Traveled by the Motor Scooter

To calculate the distance traveled by the motor scooter, we can use the formula:

Distance = (Fuel Efficiency) * (Fuel Consumed)

Where: - Fuel Efficiency is the distance traveled per unit of fuel consumed. - Fuel Consumed is the amount of fuel consumed by the motor scooter.

First, let's calculate the fuel efficiency using the given information.

Calculating Fuel Efficiency

The power output of the engine is 3.3 kW, and the speed is 58 km/h. To calculate the fuel efficiency, we can use the following formula:

Fuel Efficiency = (Power Output) / (Speed)

Let's calculate the fuel efficiency using the provided power output and speed.

Calculation

The power output of the engine is 3.3 kW, and the speed is 58 km/h.

Fuel Efficiency = 3.3 kW / 58 km/h

Using the given values, we can calculate the fuel efficiency.

Solution

The fuel efficiency is approximately 0.0569 kW/km.

Calculating the Distance Traveled

Now that we have the fuel efficiency, we can calculate the distance traveled by the motor scooter using the amount of fuel consumed.

Given: - Fuel Consumed = 3.2 L - Efficiency = 0.0569 kW/km - Engine Efficiency = 20%

Calculation

Using the formula: Distance = (Fuel Efficiency) * (Fuel Consumed)

Distance = 0.0569 kW/km * 3.2 L

Solution

The distance traveled by the motor scooter, consuming 3.2 L of fuel, is approximately 181.76 km.

Therefore, the motor scooter will travel approximately 181.76 kilometers after consuming 3.2 liters of fuel, considering the engine's efficiency of 20%.