Question

В однородное магнитное поле влетает электрон со скоростью 4,6*10 в 6ой степени м/c,направленной перпендекулярно линиям магнитной индукции.индукция магнитного поля равна 8,5*10 в минус третьей степени Тл. рассчитайте силу действующую на электрон в магнитном поле

Answer 1

$F=qBvsin \alpha \\\ F=1.6\cdot 10^{-19}\cdot8.5\cdot 10^{-3}\cdot 4.6\cdot 10^6\cdot sin90\approx6.3\cdot 10^{-15}(H)$
Ответ: 6,3*10^-15 H

Answer 2

Calculation of the Force on an Electron in a Magnetic Field

To calculate the force acting on an electron in a magnetic field, we can use the formula for the magnetic force on a moving charged particle:

F = q * v * B * sin(θ)

Where: - F is the force on the electron, - q is the charge of the electron (1.6 x 10^-19 C), - v is the velocity of the electron (4.6 x 10^6 m/s), - B is the magnetic field strength (8.5 x 10^-3 T), - θ is the angle between the velocity vector and the magnetic field vector.

In this case, the electron's velocity is perpendicular to the magnetic field lines, so the angle θ is 90 degrees, and sin(θ) = 1.

Plugging in the given values into the formula, we get:

F = (1.6 x 10^-19 C) * (4.6 x 10^6 m/s) * (8.5 x 10^-3 T) * 1

Simplifying the expression, we find:

F = 6.928 x 10^-16 N

Therefore, the force acting on the electron in the magnetic field is approximately 6.928 x 10^-16 N.