Question

Какая сила упругости возникает в пружине жесткостью 50Н/м при растяжении ее на 5 см

Answer 1

K=50Н/м, Δl= 5 см=0,05 м.F-?
F=kΔl.
F=50*0,05=2,5 Н.

Answer 2

Calculating the Spring Force

To calculate the spring force, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the amount it is stretched or compressed. The formula for Hooke's Law is:

F = kx

Where: - F is the force exerted by the spring, - k is the spring constant (also known as the stiffness or rigidity constant) in N/m, - x is the displacement from the spring's equilibrium position in meters.

In this case, the spring constant (k) is given as 50 N/m, and the displacement (x) is 5 cm, which is equal to 0.05 m.

Calculating the Spring Force using Hooke's Law

Using Hooke's Law, we can calculate the spring force as follows:

F = kx F = 50 N/m * 0.05 m F = 2.5 N

So, the spring force exerted when the spring is stretched by 5 cm is 2.5 N. This means that a force of 2.5 Newtons is required to stretch the spring by 5 cm.