Question

С какой силойможно удерживать в воде стальной рейс объёмом 0,7 м кубических

Answer 1

F = Р в воздухе - FA 

P = m * g 

m - масса 
g - ускорение свободного падения ( 10 Н / кг ) 

m = p * V 

p - плотность ( 7800 кг / м³ ) 
V - объём ( 0,7 м³ ) 

m = 7800 * 0,7 = 5460 кг 

P = 5460 * 10 = 54600 H 

FA = p * g * V 

p - плотность жидкости ( 1000 кг / м³ ) 
g = 10 H / м 
V = 0,7 м³

FA = 1000 * 10 * 0,7 = 7000 H 

F = 54600 - 7000 = 47600 H 

Answer 2

сила, с которой его можно будет удерживать, равна весу рельса Рр минус вес воды, вытесненной рельсом Pв=Vр*ро*g=0,7*1*9,8=6860 F=54600-7000=47600(Ньютон)

Answer 3

Calculating Buoyant Force on a Steel Rod in Water

To calculate the buoyant force on a steel rod in water, we can use the formula for buoyant force, which is given by the equation:

Buoyant force = weight of the water displaced

The weight of the water displaced can be calculated using the formula:

Weight of water displaced = density of water × volume of water displaced × acceleration due to gravity

Given: - Density of water (ρ) = 1000 kg/m³ (approximately) - Volume of the steel rod (V) = 0.7 m³ (given in the question) - Acceleration due to gravity (g) = 9.81 m/s² (approximately)

We can now calculate the buoyant force on the steel rod in water.

Calculation

Using the given values: - Density of water (ρ) = 1000 kg/m³ - Volume of the steel rod (V) = 0.7 m³ - Acceleration due to gravity (g) = 9.81 m/s²

We can calculate the weight of the water displaced and then the buoyant force.

Weight of water displaced = 1000 kg/m³ × 0.7 m³ × 9.81 m/s²

Weight of water displaced ≈ 6867 N

So, the buoyant force acting on the steel rod in water is approximately 6867 Newtons.

Conclusion

The buoyant force acting on a steel rod with a volume of 0.7 cubic meters in water is approximately 6867 Newtons.