Question

Снаряд, начальная скорость которого 1000м/с, пробивает стену за 0,001с, двигаясь внутри ее с ускорением 8·10м/с. Чему равна толщина стены?

Answer 1

Толщина находится по формуле Sx=V0x * t + (ax * t^2)/2
Sx= 1000 * 0,001 c + (8 * 10^5 * 0,001^2)/2 ( там возможно ошибка и ускорение = 8 * 10^5)

Sx=1,4 м

Answer 2

Calculation of Wall Thickness

To calculate the thickness of the wall, we can use the equation of motion for an object undergoing constant acceleration. The equation is:

d = v0 * t + (1/2) * a * t^2

Where: - d is the distance traveled by the object - v0 is the initial velocity of the object - t is the time taken - a is the acceleration of the object

In this case, the initial velocity (v0) is given as 1000 m/s, the time taken (t) is given as 0.001 s, and the acceleration (a) is given as 8 * 10 m/s^2.

Substituting these values into the equation, we can solve for the distance traveled by the projectile inside the wall, which will give us the thickness of the wall.

d = (1000 m/s) * (0.001 s) + (1/2) * (8 * 10 m/s^2) * (0.001 s)^2

Calculating this expression will give us the thickness of the wall.