Question

при прохождении электрического тока в алюминиевом проводе длиной 100 м. напряжение на нем составляет 1 В. чему равна масса алюминиевого провода, если сила тока в нем 15 А? плотность алюминия 2700кг/м3. ПОМОГИТЕ!

Answer 1

Гдето так

Из формулы плотности р=m / v, выразим массу: m=p*v. ( p(po)- плотность алюминия 2700кг/м3 v - объем, равный площадь сечения умноженное на длину. v=S*L.
Из формулы сопротивления выразим площадь сечения и подставим в формулу массы.
R=p1*L / S , S=p1*L / R. ( p1- удельное сопротивление алюминия =2,8*10^(-8)(Ом*м), R-сопротивление R=U/I=1/15=0,67Oм, L-длина=100м), S=2,8*10^(-8)*100/0,67=4,2*10^(-6), v=4,2*10^(-6)*100=4,2*10^(-4) получим:
m=2700*4,2*10^(-4)*=1,13кг.

Answer 2

Calculation of the Mass of the Aluminum Wire

To calculate the mass of the aluminum wire, we can use the formula:

mass = density × volume

Given: - Length of the aluminum wire = 100 m - Voltage across the wire = 1 V - Current flowing through the wire = 15 A - Density of aluminum = 2700 kg/m^3

First, let's calculate the cross-sectional area of the wire using Ohm's Law:

Voltage = Current × Resistance

Since the resistance of the wire is not given, we can rearrange the formula to solve for resistance:

Resistance = Voltage / Current

Using the given values, we can calculate the resistance:

Resistance = 1 V / 15 A = 0.0667 Ω

Next, we can use the formula for resistance:

Resistance = Resistivity × (Length / Cross-sectional Area)

Since we know the length of the wire (100 m) and the resistance (0.0667 Ω), we can rearrange the formula to solve for the cross-sectional area:

Cross-sectional Area = Length × Resistivity / Resistance

The resistivity of aluminum is not given, but we can assume it to be the same as the density of aluminum (2700 kg/m^3).

Using the given values, we can calculate the cross-sectional area:

Cross-sectional Area = 100 m × 2700 kg/m^3 / 0.0667 Ω = 405405.41 m^2

Finally, we can calculate the mass of the aluminum wire using the formula:

Mass = Density × Volume

Substituting the values, we get:

Mass = 2700 kg/m^3 × 405405.41 m^2 = 1097297297.3 kg

Therefore, the mass of the aluminum wire is approximately 1,097,297,297.3 kg.

Please note that this calculation assumes a uniform cross-sectional area for the wire and does not take into account any variations or irregularities in the wire's shape.

I hope this helps! Let me know if you have any further questions.