Question

прямолинейный проводник длиной 10 см находится между полюсами подковообразного магнита перпендикулярно вектору магнитной индукции модуль вектора магнитной индукции которого равен 0,4 тесла при пропускании по проводнику электрического тока на проводник подействовала сила ампера 0,2 ньютона каково напряжение на концах проводника если его сопротивление 20 ом

Answer 1

ДАНО                                               РЕШЕНИЕ

L= 10 см=0,1 м                                  F= I B L           

В= 0,4 Тл                                           I= F / BL

F= 0,2 H                                 I= 0,2 / 0,4*0,1=5 A

R= 20 Ом

НАЙТИ :  U                             U= I R    U= 5*20= 100 B

Answer 2

Calculation of Voltage on the Conductor

To calculate the voltage on the ends of the conductor, we can use Ohm's Law, which states that the voltage (V) across a conductor is equal to the product of the current (I) flowing through it and the resistance (R) of the conductor:

V = I * R

In this case, we are given the current (I) as 0.2 N (Newton) and the resistance (R) as 20 Ω (Ohm). We need to find the voltage (V).

Using Ohm's Law, we can substitute the given values into the equation:

V = 0.2 N * 20 Ω

Calculating the product of 0.2 N and 20 Ω, we find:

V = 4 N·Ω

Therefore, the voltage on the ends of the conductor is 4 N·Ω.

Please note that the given information does not provide enough details to calculate the voltage accurately. The given force (0.2 N) is not directly related to the current flowing through the conductor. If you have any additional information or if there are any other specific details you would like to provide, I would be happy to assist you further.