Question

Какое количество теплоты потребуеться для плавления куска олова массой 10 г,взятого при температуре плавления?Удельная тенлота плавления олова равна 0,59*10в пятой джоуль делённые на киллограм

Answer 1

Q = ∧ * m 

∧ - удельная теплота плавления ( для олова 0,59 * 10 ^ 5 Дж / кг = 59000 Дж / кг ) 
m - масса ( 10 г = 0,01 кг ) 

Q = 59000 * 0,01 = 590 Дж 

Answer 2

Calculating the Heat Required to Melt 10g of Lead:

To calculate the amount of heat required to melt a 10g piece of lead at its melting temperature, we can use the formula:

Q = m * L

Where: - Q is the heat required (in joules) - m is the mass of the substance (in grams) - L is the specific heat of fusion (in J/g)

Given: - m = 10g - L = 0.59 * 10^5 J/kg

Substitute the given values into the formula to find the heat required.

Q = 10g * (0.59 * 10^5 J/kg)

Calculating: Q = 10g * 0.59 * 10^5 J/kg

Q = 10g * 59000 J/kg Q = 590000 J/kg

So, the amount of heat required to melt a 10g piece of lead at its melting temperature is 590000 joules.

Additional Information:

The specific heat of fusion, also known as the latent heat of fusion, is the amount of heat energy required to change a substance from a solid to a liquid at its melting point. In the case of lead, the specific heat of fusion is 0.59 * 10^5 J/kg.