Question

Кубик размерами 5*2*4 см наполовину погрузился в воду.Определите Архимедову силу, действующую на кубик.

Answer 1

Дано
а- 5 см
в- 2 см
с- 4 см
g- 10 н/кг
ро жидкости- 1000 кг/м.куб
Fа?

анализ
Fа= g*ро житкости*V
V=a*b*c
решение
V= 5*2*4= 40см 
Fа=10н/кг*1000кг/м.куб*40см= 250 Н 
т.к наполовину делим на 2 и получается 250/2=125Н
)))

Answer 2

Calculation of Archimedes' Force on the Cube

To determine the Archimedes' force acting on the cube, we need to consider the buoyant force. The buoyant force is the upward force exerted on an object submerged in a fluid, and it is equal to the weight of the fluid displaced by the object.

Given that the cube has dimensions of 5 cm x 2 cm x 4 cm and is half submerged in water, we can calculate the volume of the cube that is submerged.

The volume of the cube is given by the formula V = l x w x h, where l is the length, w is the width, and h is the height. In this case, the length is 5 cm, the width is 2 cm, and the height is 4 cm.

The volume of the cube is therefore V = 5 cm x 2 cm x 4 cm = 40 cm³.

Since the cube is half submerged in water, the volume of water displaced is half of the volume of the cube, which is 40 cm³ / 2 = 20 cm³.

Now, we can calculate the buoyant force using the formula F = ρ x g x V, where F is the buoyant force, ρ is the density of the fluid, g is the acceleration due to gravity, and V is the volume of the fluid displaced.

The density of water is approximately 1 g/cm³, and the acceleration due to gravity is approximately 9.8 m/s².

Converting the volume of water displaced to m³, we have V = 20 cm³ / 1000000 = 0.00002 m³.

Substituting the values into the formula, we get F = 1 g/cm³ x 9.8 m/s² x 0.00002 m³ = 0.000196 N.

Therefore, the Archimedes' force acting on the cube is approximately 0.000196 N.